Examples of Final Solution in the following topics:
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- It is used to prevent any change in the pH of a solution, regardless of solute.
- In the first method, prepare a solution with an acid and its conjugate base by dissolving the acid form of the buffer in about 60% of the volume of water required to obtain the final solution volume.
- Once the pH is correct, dilute the solution to the final desired volume.
- Both solutions must contain the same buffer concentration as the concentration of the buffer in the final solution.
- To get the final buffer, add one solution to the other while monitoring the pH.
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- This process keeps the amount of solute constant, but increases the total amount of solution, thereby decreasing its final concentration.
- Dilution can also be achieved by mixing a solution of higher concentration with an identical solution of lesser concentration.
- M1 denotes the concentration of the original solution, and V1 denotes the volume of the original solution; M2 represents the concentration of the diluted solution, and V2 represents the final volume of the diluted solution.
- 175 mL of a 1.6 M aqueous solution of LiCl is diluted with water to a final volume of 1.0 L.
- What is the final concentration of the diluted solution?
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- We found the equation of the best fit line for the final exam grade as a function of the grade on the third exam.
- Suppose you want to estimate, or predict, the final exam score of statistics students who received 73 on the third exam.
- We predict that statistic students who earn a grade of 73 on the third exam will earn a grade of 179.08 on the final exam, on average.
- What would you predict the final exam score to be for a student who scored a 66 on the third exam?
- What would you predict the final exam score to be for a student who scored a 90 on the third exam?
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- These solutions are known as buffers.
- It is possible to calculate how the pH of the solution will change in response to the addition of an acid or a base to a buffer solution.
- What is the pH of the solution?
- Solving for the pH of a 0.0020 M solution of NaOH:
- Calculate the final pH of a solution generated by the addition of a strong acid or base to a buffer.
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- Molarity is defined as the moles of a solute per volume of total solution.
- In chemistry, concentration of a solution is often measured in molarity (M), which is the number of moles of solute per liter of solution.
- A solution that contains 1 mole of solute per 1 liter of solution (1 mol/L) is called "one Molar" or 1 M.
- To calculate the molarity of a solution, the number of moles of solute must be divided by the total liters of solution produced.
- This relationship is represented by the equation c1V1 = c2V2 , where c1 and c2 are the initial and final concentrations, and V1 and V2 are the initial and final volumes of the solution.
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- The x values in the data are between 65 and 75. 90 is outside of the domain of the observed x values in the data (independent variable), so you cannot reliably predict the final exam score for this student.
- The final exam score is predicted to be 261.19.
- The largest the final exam score can be is 200.
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- Precipitation reactions transform ions into an insoluble salt in aqueous solution.
- A precipitation reaction can occur when two solutions containing different salts are mixed, and a cation/anion pair in the resulting combined solution forms an insoluble salt; this salt then precipitates out of solution.
- This reaction can be also be written in terms of the individual dissociated ions in the combined solution.
- A final way to represent a precipitation reaction is known as the net ionic equation.
- For instance, if silver nitrate is added to a solution of an unknown salt and a precipitate is observed, the unknown solution might contain chloride (Cl-).
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- Rinse the burette with the standard solution, the pipette with the unknown solution, and the conical flask with distilled water.
- At this stage, we want a rough estimate of the amount of known solution necessary to neutralize the unknown solution.
- Record the initial and final readings on the burette, prior to starting the titration and at the end point, respectively.
- (Subtracting the initial volume from the final volume will yield the amount of titrant used to reach the endpoint.)
- The pH of a weak acid solution being titrated with a strong base solution can be found at each indicated point.
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- The Henderson–Hasselbalch equation connects the measurable value of the pH of a solution with the theoretical value pKa.
- The equation is also useful for estimating the pH of a buffer solution and finding the equilibrium pH in an acid-base reaction.
- Distributing the negative sign gives the final version of the Henderson-Hasselbalch equation:
- An example of how to use the Henderson-Hasselbalch equation to solve for the pH of a buffer solution is as follows:
- What is the pH of a buffer solution consisting of 0.0350 M NH3 and 0.0500 M NH4+ (Ka for NH4+ is 5.6 x 10-10)?
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- A strong acid will react with a weak base to form an acidic (pH < 7) solution.
- A small amount of the acid solution of known concentration is placed in the burette (this solution is called the titrant).
- As the equivalence point is approached, the pH will change more gradually, until finally one drop will cause a rapid pH transition through the equivalence point.
- In the example of the titration of HCl into ammonia solution, the conjugate acid formed (NH4+) reacts as follows:
- A depiction of the pH change during a titration of HCl solution into an ammonia solution.