Examples of L-arabinose in the following topics:
-
- The L-arabinose operon, also called ara operon, encodes enzymes needed for the catabolism of arabinose to xylulose 5-phosphate.
- The L-arabinose operon, also called ara operon, is a gene sequence encoding enzymes needed for the catabolism of arabinose to xylulose 5-phosphate, an intermediate of the pentose phosphate pathway.
- When arabinose is present, arabinose binds AraC and prevents it from interacting.
- When arabinose is present, AraC acts as an activator and it builds a complex: AraC + arabinose.
- Thus the activation depends on the presence of arabinose and cAMP.
-
- The mirror images of these configurations were then designated the L-family of aldoses.
- A left directed hydroxyl group (the mirror image) then represented the L-family.
- Thus Ruff degradation of the pentose arabinose gives the tetrose erythrose.
- This defines the configuration of both ribose and arabinose.
- Ruff shortening of glucose gave arabinose, and Kiliani-Fischer synthesis applied to arabinose gave a mixture of glucose and mannose.
-
- Each of these compounds has an enantiomer, which is a member of the "L"-family so, as expected, there are eight stereoisomers in all.
- Thus, ribose and arabinose are epimers at C-2, and arabinose and lyxose are epimers at C-3.
- However, arabinose and xylose are not epimers, since their configurations differ at both C-2 and C-3.
-
- {(l+|m|)!
- $\displaystyle {\bf L}^2 Y_{lm} = l(l+1) Y_{lm} ~\text{ and }~L_z Y_{lm} = m Y_{lm} $
- so the total angular momentum of the state is related to $l$ and the $z$-component of the angular momentum is related to $m$.Both $l$ and $m$ take on integral values with $-l < m < l$.
- $\displaystyle \frac{1}{2} \frac{d^2 R_{nl}}{dr^2} + \left [ E - V(r) - \frac{l(l+1)}{2r^2} \right ] R_{nl} = 0$
- $V(r)$ is the radial potential and the term proportional to $l(l+1)$ is the centripetal potential.
-
- Are L and C independent events?
- Are L and C mutually exclusive events?
-
- with $\omega/c = \pi n /l$, $\omega/c = \pi n /l$, $\omega/c = \pi n /l$, arbitrary constants.
- $\displaystyle{u(x,t) = DA \sin\left(\frac{\pi n}{l} x\right) \cos\left(\frac{\pi nc}{l}t\right) + DB \sin\left(\frac{\pi n}{l} x\right) \sin \left(\frac{\pi nc}{l} t\right). }$
- $\displaystyle{u(x,t) = A \sin\left(\frac{\pi n}{l} x\right) \cos\left(\frac{\pi nc}{l}t\right) + B \sin\left(\frac{\pi n}{l} x\right) \sin\left(\frac{\pi nc}{l} t\right). }$
- $\displaystyle{A \sin\left(\frac{\pi n}{l} x\right) \cos\left(\frac{\pi nc}{l}t\right) + B \sin\left(\frac{\pi n}{l} x\right) \sin\left(\frac{\pi nc}{l} t\right)}$
- $\displaystyle{\sum _ n A_n \sin\left(\frac{\pi n}{l} x\right) \cos\left(\frac{\pi nc}{l}t\right) + B_n \sin\left(\frac{\pi n}{l} x\right) \sin\left(\frac{\pi nc}{l} t\right)}$
-
- However, mol/L is a more common unit for molarity.
- 1 mol/L = 1 mol/dm3 = 1 mol dm−3 = 1 M = 1000 mol/m3
- In order for the scientist to make 150.0 mL of 2.0 M HCl, he will need 60.0 mL of 5.0 M HCl and 90.0 mL of water.
- Water was added to 25 mL of a stock solution of 5.0 M HBr until the total volume of the solution was 2.5 L.
- We are given the following: c1= 5.o M, V1= 0.025 L, V2= 2.50 L.
-
- To derive the relationship, let's take a cube of steel that has sides of length L.
- $\begin{aligned} V+ \Delta V &= (L + \Delta L)^3 \\ &= L^3 + 3L^2\Delta L + 3L(\Delta L )^2 +(\Delta L)^3 \\ &\approx L^3 + 3L^2\Delta L \\ &= V + 3 V \frac {\Delta L}{L} \end{aligned}$.
- The approximation holds for a sufficiently small $\Delta L$ compared to L.
-
- To derive the relationship, let's take a square of steel that has sides of length L.
- The original area will be A = L2,and the new area, after a temperature increase, will be $\begin{aligned} A + \Delta A &= (L + \Delta L)^2 \\ &= L^2 + 2L\Delta L + (\Delta L )^2 \\ &\approx L^2 + 2L\Delta L \\ &= A + 2 A \frac {\Delta L}{L} \end{aligned}$
- The approximation holds for a sufficiently small $\Delta L$ campared to L.
- Since $\frac{\Delta A}{A} = 2 \frac{\Delta L}{L}$ from the equation above (and from the definitions of the thermal coefficients), we get $\alpha_A = 2 \alpha_L$.
-
- The species of Leishmania that can cause leishmaniasis include: L. donovani complex with 2 species (L. donovani, L. infantum, also known as L. chagasi); the L. mexicana complex with 3 main species (L. mexicana, L. amazonensis, and L. venezuelensis); L. tropica; L. major; L. aethiopica; and the subgenus Viannia with 4 main species (L.
- (V.) braziliensis, L.
- (V.) guyanensis, L.
- (V.) panamensis, and L.